ƒ

बहुपद गुणनखंड कैलकुलेटर

GCF · वर्गों का अंतर · घनों का योग/अंतर · द्विघात · समूहीकरण · परिमेय मूल

कोई भी बहुपद दर्ज करें और चरण-दर-चरण हल के साथ पूर्ण गुणनखंड रूप प्राप्त करें। घात 1-6 समर्थित, सर्वोत्तम विधि स्वतः पहचानी जाती है।

त्वरित उदाहरण

घातांक के लिए ^ उपयोग करें · spaces वैकल्पिक · घात 1-6 समर्थित

गुणनखंड विधियाँ संदर्भ कार्ड
1. GCF बाहर निकालें
यह सबसे पहले करें
6x³+9x² = 3x²(2x+3)
2. वर्गों का अंतर
a²−b² = (a+b)(a−b)
4x²−9 = (2x+3)(2x−3)
3. पूर्ण वर्ग त्रिपद
a²±2ab+b² = (a±b)²
x²+6x+9 = (x+3)²
4. घनों का योग
a³+b³ = (a+b)(a²−ab+b²)
x³+27 = (x+3)(x²−3x+9)
5. घनों का अंतर
a³−b³ = (a−b)(a²+ab+b²)
x³−8 = (x−2)(x²+2x+4)
6. द्विघात त्रिपद
द्विघात सूत्र ax²+bx+c के लिए
x²−5x+6 = (x−2)(x−3)
7. समूहीकरण द्वारा गुणनखंड
4 पद वाले बहुपद को जोड़ों में विभाजित करें
x³+x²−x−1 = (x+1)²(x−1)
8. परिमेय मूल प्रमेय
घात 3+ के लिए ±p/q परीक्षण
x³−6x²+11x−6 = (x−1)(x−2)(x−3)

बहुपद गुणनखंड क्या है?

Polynomial factoring is the process of rewriting a polynomial as a product of two or more simpler polynomials. It is the algebraic inverse of expanding or multiplying polynomials. For example, x² − 9 factors into (x + 3)(x − 3), because multiplying those two binomials gives back x² − 9. Factoring is one of the most important skills in algebra and forms the foundation for solving polynomial equations, simplifying rational expressions, finding roots, and working with polynomials in calculus.

बहुपद का गुणनखंड क्यों करें?

  • Solving equations: Setting each factor equal to zero gives the roots instantly. If p(x) = (x−3)(x+2), then x = 3 and x = −2.
  • Simplifying rational expressions: Common polynomial factors in a fraction's numerator and denominator can be cancelled.
  • Finding x-intercepts: The real roots of a polynomial are its x-intercepts on a graph.
  • Calculus applications: Partial fraction decomposition requires factored denominators. Limits, derivatives, and integrals are often simplified by factoring.
  • Understanding multiplicity: Repeated factors like (x−2)² indicate the root x = 2 has multiplicity 2, meaning the graph touches but does not cross the x-axis there.

8 गुणनखंड विधियाँ

1. Greatest Common Factor (GCF)

Always try to factor out the GCF first. The GCF is the largest monomial that divides every term. Example: 6x³ + 9x² = 3x²(2x + 3). The GCF here is 3x². This step reduces the degree of the remaining polynomial and simplifies all further factoring.

2. वर्गों का अंतर

Any binomial of the form a² − b² factors as (a + b)(a − b). Both terms must be perfect squares, and the sign between them must be minus. Example: 4x² − 25 = (2x)² − 5² = (2x + 5)(2x − 5). Note that a sum of squares a² + b² does not factor over the real numbers.

3. पूर्ण वर्ग त्रिपद

A trinomial a² + 2ab + b² factors as (a + b)², and a² − 2ab + b² factors as (a − b)². Example: x² + 6x + 9 = (x + 3)². To check: the first and last terms must be perfect squares, and the middle term must equal twice their product.

4. घनों का योग

a³ + b³ = (a + b)(a² − ab + b²). Remember SOAP: Same, Opposite, Always Positive for the signs. Example: x³ + 27 = x³ + 3³ = (x + 3)(x² − 3x + 9). The trinomial factor is always irreducible over the reals.

5. घनों का अंतर

a³ − b³ = (a − b)(a² + ab + b²). Example: x³ − 8 = x³ − 2³ = (x − 2)(x² + 2x + 4). The signs: first factor has minus, trinomial starts positive, all remaining signs positive.

6. द्विघात त्रिपद (Quadratic Formula)

For any quadratic ax² + bx + c, the discriminant is Δ = b² − 4ac. If Δ ≥ 0, real roots exist: r = (−b ± √Δ) / (2a), and the polynomial factors as a(x − r₁)(x − r₂). If Δ < 0, the quadratic is irreducible over the reals.

7. Factoring by Grouping

This technique applies to 4-term polynomials. Group into two pairs, factor the GCF from each pair, then extract the common binomial. Example: 2x³ + 6x² − 2x − 6 = (2x³ + 6x²) + (−2x − 6) = 2x²(x + 3) − 2(x + 3) = (2x² − 2)(x + 3) = 2(x² − 1)(x + 3) = 2(x + 1)(x − 1)(x + 3).

8. परिमेय मूल प्रमेय and Synthetic Division

For degree 3 and higher, the Rational Root Theorem lists all possible rational roots as ±p/q, where p divides the constant term and q divides the leading coefficient. Each candidate is tested; if p(r) = 0, then (x − r) is a factor. Synthetic division then reduces the polynomial degree by one, and the process repeats until completely factored.

संदर्भ तालिका: सामान्य गुणनखंड रूप

FormFactored FormExample
a²−b²(a+b)(a−b)x²−9 = (x+3)(x−3)
a²+2ab+b²(a+b)²x²+6x+9 = (x+3)²
a³+b³(a+b)(a²−ab+b²)x³+8 = (x+2)(x²−2x+4)
a³−b³(a−b)(a²+ab+b²)x³−27 = (x−3)(x²+3x+9)
a⁴−b⁴(a²+b²)(a+b)(a−b)x⁴−16 = (x²+4)(x+2)(x−2)

अक्सर पूछे जाने वाले प्रश्न

बहुपद गुणनखंड क्या है?
Polynomial factoring rewrites a polynomial as a product of simpler polynomials. For example, x² − 9 = (x+3)(x−3). It is the reverse of polynomial multiplication and is fundamental for solving equations, simplifying rational expressions, and finding roots.
What is the difference of squares factoring pattern?
The pattern a² − b² = (a+b)(a−b) applies to any binomial where both terms are perfect squares connected by subtraction. Examples: x²−9=(x+3)(x−3), 4x²−25=(2x+5)(2x−5), x⁴−16=(x²+4)(x+2)(x−2). A sum of squares a²+b² does not factor over the reals.
How do you factor a sum or difference of cubes?
Sum of cubes: a³+b³ = (a+b)(a²−ab+b²). Difference of cubes: a³−b³ = (a−b)(a²+ab+b²). Memory trick SOAP: Same sign, Opposite sign, Always Positive. For example, x³−8 = (x−2)(x²+2x+4) and x³+27 = (x+3)(x²−3x+9). The trinomial is always irreducible over the reals.
What is the Rational Root Theorem and how is it used?
For a polynomial with integer coefficients, any rational root p/q must have p as a factor of the constant term and q as a factor of the leading coefficient. This gives a finite list to test. Once a root r is found, (x−r) is a factor and synthetic division reduces the degree, allowing further factoring.
What does it mean when a polynomial is irreducible?
A polynomial is irreducible over the reals when it cannot be factored into lower-degree real polynomials. All linear polynomials are irreducible. A quadratic is irreducible when its discriminant b²−4ac < 0 (no real roots). Higher-degree polynomials factor into irreducible linear and quadratic pieces.
How does factoring by grouping work?
Split the polynomial into two pairs and factor the GCF from each pair. If both pairs share a common binomial factor, extract it. Example: 2x³+6x²−2x−6 = 2x²(x+3)−2(x+3) = (2x²−2)(x+3) = 2(x+1)(x−1)(x+3). The groups must be chosen so both yield the same binomial factor.
What is the GCF and why factor it out first?
The Greatest Common Factor (GCF) is the largest monomial dividing every term. Factoring it out first lowers the degree and simplifies coefficients, making all subsequent techniques easier. Example: 6x³+9x² has GCF 3x², giving 3x²(2x+3). Always start with the GCF before any other technique.