Escape Velocity Calculator

Calculate escape velocity v = √(2GM/r) for any planet, moon, or custom body. Compare orbital velocity and cosmic velocities.

Quick Presets

Mass M
kg
Radius R
m
Altitude h above surface

Select a planet or enter custom M and R, then see escape and orbital velocities instantly.

What Is Escape Velocity?

Escape velocity is the minimum speed an object must reach to break free from a gravitational field without any further propulsion. Once an object exceeds this speed, it has enough kinetic energy to overcome the gravitational potential energy binding it to the planet — it will never fall back, even without engines.

Crucially, escape velocity does not depend on the direction of launch (ignoring atmosphere) or on the mass of the escaping object — only on the mass of the body being escaped and the launch radius.

v = √(2GM/r)
Escape velocity
11.19 km/s
Earth surface
v_esc = √2 · v_orb
Escape vs orbital

Deriving v = √(2GM/r) from Energy Conservation

At escape velocity the total mechanical energy is exactly zero — kinetic energy equals gravitational potential energy:

½mv² − GMm/r = 0

Cancel mass m (explaining mass-independence), rearrange:

v = √(2GM/r)

G = 6.6743×10⁻¹¹ N·m²/kg², M = planet mass (kg), r = distance from center (m). At the surface r = R (planet radius). Adding altitude h gives r = R + h.

Escape Velocity for Every Planet

Body v_esc (km/s) v_orb (km/s) g (m/s²)
Sun617.7436.8274.0
Mercury4.253.013.70
Venus10.367.338.87
Earth11.197.919.81
Moon2.381.681.62
Mars5.033.553.72
Jupiter59.5442.1024.79
Saturn35.4925.1010.44
Pluto1.220.860.62

Orbital vs Escape Velocity

Orbital velocity at radius r is v_orb = √(GM/r). Escape velocity is always √2 ≈ 1.414 times the orbital velocity at the same radius. This means a spacecraft already in orbit at 400 km altitude needs only a 41.4% increase in speed to escape Earth entirely.

Earth Low Orbit (400 km)

v_orb = 7,663 m/s
v_esc = 10,837 m/s
Ratio = √2 = 1.414

Earth Surface

v_orb = 7,909 m/s
v_esc = 11,186 m/s
Ratio = √2 = 1.414

The Three Cosmic Velocities

1

First Cosmic Velocity — 7.91 km/s

The minimum speed to orbit Earth at its surface. Derived from v = √(GM/R). Any orbital satellite must travel at or above this speed.

2

Second Cosmic Velocity — 11.19 km/s

Earth's escape velocity. A spacecraft launched at this speed (with no further propulsion) will escape Earth's gravity and continue into interplanetary space.

3

Third Cosmic Velocity — 16.62 km/s

The speed needed (from Earth's surface, accounting for Earth's orbital velocity around the Sun) to escape the Solar System entirely. Pioneer and Voyager probes exceeded this velocity.

Black Holes and the Schwarzschild Radius

A black hole forms when matter is compressed so densely that the escape velocity exceeds the speed of light c. The Schwarzschild radius is found by setting v_esc = c in the escape velocity formula:

r_s = 2GM / c²

For Earth, r_s ≈ 8.9 mm. For the Sun, r_s ≈ 3 km. At radii smaller than r_s (the event horizon), not even light can escape — hence "black" hole.

Worked Examples

Example 1 — Earth surface

M = 5.972×10²⁴ kg, R = 6.371×10⁶ m
v = √(2×6.674e-11×5.972e24 / 6.371e6)
v_esc = 11,186 m/s = 11.19 km/s

Example 2 — Moon surface

M = 7.342×10²² kg, R = 1.737×10⁶ m
v = √(2×G×M / R)
v_esc = 2,376 m/s — Apollo engines sufficient!

Example 3 — Mars surface

M = 6.417×10²³ kg, R = 3.390×10⁶ m
v = √(2×G×M / R)
v_esc = 5,028 m/s = 5.03 km/s

Example 4 — ISS altitude (400 km)

r = 6.371e6 + 400e3 = 6.771×10⁶ m
v_esc = 10,837 m/s
v_orb = 7,663 m/s (ISS orbital speed)

Frequently Asked Questions

Escape velocity is the minimum speed an object must have to break free from a celestial body's gravitational pull without any further propulsion. It is derived from energy conservation: at escape velocity, the object's kinetic energy exactly equals the gravitational potential energy binding it to the body.
The formula is v_esc = √(2GM/r), where G = 6.6743×10⁻¹¹ N·m²/kg² is the gravitational constant, M is the mass of the celestial body in kg, and r is the distance from the body's center in meters. At the surface, r equals the body's radius R. Adding altitude h gives r = R + h.
Because when you equate kinetic energy ½mv² to gravitational potential energy GMm/r, the object's mass m cancels out on both sides, leaving v = √(2GM/r). This is why a rocket and a baseball leaving Earth's surface need the same escape speed — only the planet's mass and the launch radius matter.
Orbital velocity v_orb = √(GM/r) is the speed needed to maintain a circular orbit at radius r. Escape velocity v_esc = √(2GM/r) is exactly √2 times the orbital velocity at the same radius. To escape Earth from the surface you need ~11.19 km/s; to orbit at the surface you need ~7.91 km/s.
The first cosmic velocity (~7.91 km/s) is the orbital speed at Earth's surface. The second cosmic velocity (~11.19 km/s) is Earth's escape velocity. The third cosmic velocity (~16.62 km/s from Earth's surface, or ~42.1 km/s relative to the Sun) is the speed needed to escape the entire Solar System from Earth's orbit.
Earth's escape velocity at the surface is approximately 11,186 m/s (11.19 km/s) or about 40,270 km/h. This is roughly 33 times the speed of sound. At the altitude of the ISS (400 km), it drops to about 10,837 m/s.
The theoretical escape velocity formula assumes no atmosphere. In practice, rockets must overcome atmospheric drag in addition to gravity, requiring more fuel. The actual delta-v needed to leave Earth is higher than 11.19 km/s, which is why rockets launch vertically, follow a gravity turn, and shed stages to reduce mass.
No — at a black hole's event horizon (Schwarzschild radius r_s = 2GM/c²), the escape velocity equals the speed of light c ≈ 3×10⁸ m/s. Since nothing travels faster than light, nothing — not even photons — can escape from inside the event horizon.